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AL 8810 ethyl amide

Catalog No. T38114

AL 8810 is an 11β-fluoro analog of prostaglandin F2α (PGF2α) which acts as a potent and selective antagonist at the FP receptor. AL 8810 ethyl amide is an analog of AL 8810 in which the C-1 carboxyl group has been modified to an N-ethyl amide. This modification is analogous to the PG N-ethyl amides, as typified by Bimatoprost, that have been introduced as alternative PG ocular hypotensive prodrugs. In contrast to AL 8810 which contracted the cat iris, AL 8810 ethyl amide showed no contraction activity at concentrations up to 10-4 M and did not antagonize the activity of PGF2α-ethanolamide in this system.

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AL 8810 ethyl amide, CAS N/A

Pack Size	Availability	Price/USD
1 mg	35 days	$ 223.00
5 mg	35 days	$ 980.00
10 mg	35 days	$ 1,880.00

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Biological Description

Chemical Properties

Storage & Solubility Information

Description

Molecular Weight

N/A

Storage

Powder: -20°C for 3 years | In solvent: -80°C for 1 year

Solubility Information

Ethanol:PBS (pH 7.2)(1:2): 0.3 mg/mL

Ethanol: 15 mg/mL

DMF: 15 mg/mL

DMSO: 10 mg/mL

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You can also refer to dose conversion for different animals. More

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Working concentration: mg/ml;

Method for preparing DMSO master liquid: mg drug pre-dissolved in μL DMSO (Master liquid concentration mg/mL)，Please contact us first if the concentration exceeds the DMSO solubility of the batch of drug.

Method for preparing in vivo formulation：Take μL DMSO master liquid, next add μL PEG300， mix and clarify, next add μL Tween 80，mix and clarify, next add μL ddH₂O, mix and clarify.

Note:

Be sure to add the solvent(s) in order. Physical methods such as vortex, ultrasound or hot water bath can be used to aid dissolving.

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What is the mass of compound required to make a 10 mM stock solution in 10 ml of water given that the molecular weight of the compound is 197.13 g/mol?
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The answer of 19.713 mg appears in the Mass box

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An example of a dilution calculation using the Tocris dilution calculator
What volume of a given 10 mM stock solution is required to make 20ml of a 50 μM solution?
Using the equation C1V1 = C2V2, where C1=10 mM, C2=50 μM, V2=20 ml and V1 is the unknown:
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The answer of 100 microliter (0.1 ml) appears in the Volume (start) box

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Molecular mass (molecular weight) is the mass of one molecule of a substance and is expressed n the unified atomic mass units (u). (1 u is equal to 1/12 the mass of one atom of carbon-12)
Molar mass (molar weight) is the mass of one mole of a substance and is expressed in g/mol.

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Tech Support

Please see Inhibitor Handling Instructions for more frequently ask questions. Topics include: how to prepare stock solutions, how to store products, and cautions on cell-based assays & animal experiments, etc.

Keywords

AL 8810 ethyl amide AL 8810 ethyl Amide inhibitor inhibit

Products are chemical reagents for research use only and are not intended for human use. We do not sell to patients.